Solving "Impossible" Differential Equations with Mathematica
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You should have gotten the following if you did it correctly.
sol1/.x->2
0.820046
This same method can be used to find the value of the solution at any x-value we choose. Now you do it for every x-value given in the following list:
- x = 0
- x = 1
- x = 1.5
- x = 3
- x = 4
- x = 5
- x = 6
- x = -1
Go ahead and switch to Mathematica now and do each of these, flipping back here if and when you need to check the exercises. Of course, come back here when you're done.
Welcome back! Moving on...